Did You Have the Street Light Rule When You Were Little?

That, or they would call my name from the window a few times. Everyone's parents in the neighborhood did that for some reason.. I think it's weird!

Did You Have the Street Light Rule When You Were Little? 1

1. A street light is mounted at the top of a 15 foot tall pole. A man 6 ft tall walks away from the pole with a s?

the respond is self sufficient of the area from the pole, and of the guy's direction of commute. you will discover this by noting that the guy's head travels freely in a airplane parallel to the floor, and six ft above it. So the lamp initiatives factors in that airplane onto factors on the floor, magnifying each little thing in the 6-feet-severe airplane by the comparable element, 15/(15 - 6) = 15/9 = 5/3. So the fast answer is (5/3)*4 feet/s = 20/3 feet/s a photograph will make this sparkling. Idealize the desirable of the guy's head and the gentle as factors, the floor as a horizontal airplane, and draw a diagram of a vertical go-section (a vertical airplane) in the path of the lamp and the guy's head. the floor is a line, the lamp is element A, the desirable of the guy's head is B, and AB prolonged to the floor line, crosses it at D, that's the top of the shadow. Now hit upon element C straight away below A, and six feet above the floor line. place F on the foot of the pole, on the floor, straight away below A. Triangles ABC and ADF are comparable, because of the fact: AB lies alongside advert, AC lies alongside AF, and BC and DF are parallel, the two being horizontal. So DF/BC = AF/advert = 15 feet / 9 feet = 5/3 yet DF is the area of the shadow tip from the backside of the pole, and BC is the area of the guy's head from the pole. So now call x the size of BC, and y the size of DF. Then y = (5/3)x dy/dt = (5/3)dx/dt dx/dt = the guy's velocity = 4 feet/s. So dy/dt = (5/3)*4 feet/s = 20/3 feet/s = 6ft 8in /s

2. Do street light poles influence lighting output?

When maintaining street lights, we found one or two sets of LED street lights on the side of the road will not be on. There is a fault or damage in the LED street lamp holder, so why does the street lamp fail. Below are the reasons will be.n n 1The quality of LED chip is poor. Now the quality of LED chips is emerging in endlessly in the market. Some LED chips have poor quality and short service life. They will be damaged in a short time and will not be bright naturally. n n 2Poor heat dissipation. The heat dissipation performance of LED street light housing is not good, and the internal heat of LED street lamp shell is too high, which is easy to lead to the damage of LED chip and the phenomenon of no light.3Power drive issues. Because LED street lights need to be driven by the power supply to turn the high voltage of the mains power into the low voltage to work, and this link has a great test on the performance of the power supply, and the damage of the power drive device will also cause other LED street light components not to work normally.n n The above are several frequent failures. Of course, there are other factors that cause the LED street lamp suddenly not to light up. For specific analysis, if you want the LED street lamp to have a long service life, you should try to choose a good quality street lamp manufacturer when you purchase it, and pay attention to regular maintenance at ordinary times, so as to ensure the stability of the LED street lamp. The general street lamp has always guaranteed the quality, and the perfect after-sales service will also ensure the service. Do street light poles influence lighting output?

Did You Have the Street Light Rule When You Were Little? 2

3. Did you have the street light rule when you were little?

LOL!!!...never did like that rule. I believe its more of a city kid thing.

4. What is the height of a man walking away from a street light 12 ft high, if his shadow is moving twice as fast as he is? [duplicate]

Assume that the man starts walking from the base of the lamppost, where he has no shadow. Some time after that, the man is at distance $x$ from the lamppost. The tip of his shadow, having traveled twice as fast during the same time, will be at distance $2x$ from the lampost. By similarity of the obvious triangles, $frac2x12=frac2x-xh$ therefore $h=6$

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